
11+ Algebra Basics: Missing Numbers, Equations and Worked Answers
Understand expressions, substitution and simple equations, then try eight original algebra questions with step-by-step answers and checking methods.
Original learning material for families preparing for 11-plus exams taken in 2027. These examples are not official exam questions; check your school’s current assessment guidance for the skills and format it uses.
Algebra gives a name to a number you do not yet know, or a quantity that can vary. If a box plus seven equals nineteen, you already know how to find the missing value. Writing x + 7 = 19 records the same problem with a letter instead of a box.
Know what the symbols are saying
| Notation | Meaning |
|---|---|
| x | An unknown or variable; the question tells you how it is used |
| 4x | 4 multiplied by x, not 4 plus x |
| x + 6 | An expression: a calculation involving x |
| x + 6 = 17 | An equation: the two sides have equal values |
| 2(x + 3) | Two lots of the complete amount x + 3 |
An expression has no equals sign telling you what it must equal. You can evaluate it when given a value, or sometimes simplify it. An equation gives a relationship you can use to find an unknown. Do not try to “solve x” in 3x + 5 unless you are given more information.
Worked example: substitute a value
Find the value of 4a + 3 when a = 6. Replace the letter with six: 4 × 6 + 3 = 24 + 3 = 27. Multiplication happens before addition here. The expression is not 46 + 3, because writing a number next to a letter indicates multiplication.
Brackets can change the result. With a = 6, the expression 4(a + 3) gives 4 × (6 + 3) = 4 × 9 = 36. Compare 27 and 36: the first expression adds three once; the second adds three inside each of four groups.
Worked example: solve and keep the balance
Solve 5x + 8 = 43. Subtract eight from both sides: 5x = 35. Divide both sides by five: x = 7. The point of doing the same thing to each side is to preserve equality. You are changing the equation into a simpler equivalent one, not merely moving symbols around.
Now substitute seven into the original equation: 5 × 7 + 8 = 35 + 8 = 43. This confirms the value satisfies the equation. If you check only the final line x = 7, you have not checked the original relationship.
Worked example: reverse a function machine
A machine multiplies an input by four, then subtracts nine. Its output is 31. Undo the last step first: 31 + 9 = 40. Undo multiplying by four: 40 ÷ 4 = 10. The input is ten. Checking forwards gives 10 × 4 − 9 = 31.
The order matters. Dividing 31 by four before adding nine would reverse the individual operations in the wrong order. A useful question is: “What was the last thing done to the number?” That is the first thing to undo.
Form an equation from a short story
A workshop charges £6 to enter and £3 for each model made. If a visitor pays £24 altogether, let m be the number of models. The charge is 6 + 3m = 24. Subtract six to get 3m = 18, then divide by three: m = 6. Check the answer as a cost: £6 + six lots of £3 = £24.
Keep the meaning of the letter clear. Here m counts models; it does not mean money. Labelling a variable prevents a numerical answer from being attached to the wrong quantity in a longer problem.
Eight algebra questions with answers
1. Evaluate 3b + 7 when b = 5.
Show answer and explanation
22.
Replace b with five: 3 × 5 + 7 = 15 + 7 = 22. Complete multiplication before addition.
2. Solve x + 9 = 26.
Show answer and explanation
x = 17.
Subtract nine from both sides. Check: 17 + 9 = 26.
3. Solve 6n = 54.
Show answer and explanation
n = 9.
6n means six multiplied by n. Divide both sides by six. Check: 6 × 9 = 54.
4. Solve 4y − 7 = 29.
Show answer and explanation
y = 9.
Add seven to both sides: 4y = 36. Divide by four. Check: 4 × 9 − 7 = 36 − 7 = 29.
5. Solve 3(t + 2) = 30.
Show answer and explanation
t = 8.
Divide both sides by three: t + 2 = 10. Subtract two. Check with the brackets intact: 3 × (8 + 2) = 30.
6. A machine adds five, then multiplies by three. The output is 42. What was the input?
Show answer and explanation
9.
Undo multiplying by three: 42 ÷ 3 = 14. Undo adding five: 14 − 5 = 9. Check: (9 + 5) × 3 = 42.
7. Three identical badges and a £4 pouch cost £19. Write and solve an equation for the price b of one badge in pounds.
Show answer and explanation
3b + 4 = 19, so b = 5.
Subtract four: 3b = 15. Divide by three: b = 5. The original purchase costs 3 × £5 + £4 = £19.
8. A pupil says 4x + 3 = 7x. Is that an algebraic identity? Explain using x = 2.
Show answer and explanation
No. With x = 2, the sides are 11 and 14.
4x and 3 are unlike terms, so they cannot be combined as 7x. Substitution gives 4 × 2 + 3 = 11, while 7 × 2 = 14. They happen to be equal when x = 1, but an identity must hold for every allowed value.
Three mistakes to watch for
- Subtracting the coefficient: in 5x = 35, undo multiplication by dividing by five, not subtracting five.
- Checking a changed equation but not the original: a slip in an earlier line can survive a check of only the last step.
- Forgetting brackets: 2(x + 4) includes two lots of four; it is not the same expression as 2x + 4.
Where this fits in preparation
These beginner skills can support multi-step word problems. For more original question practice, try the fresh maths set, which includes equations alongside other skills, or return to the Maths hub. A practice score is not a prediction of an entrance-exam result.
The DfE mathematics programme includes algebraic missing-number work and simple formulae in Year 6. It is a curriculum reference, not a guarantee that a particular 11-plus test uses these question types. Source checked 21 October 2026. No educator endorsement or official-paper affiliation is claimed.
Ready to practise?
Choose original practice and use the answer explanations to decide what to work on next. These are not official school papers.
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